chapter 4 acid-base__ titrimetry.ppt
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1、Chapter 3 Chapter 3 TitrimetricTitrimetric Analysis Analysis3.2 Acid-Base Titration3.2.1 Acid-Base Equilibria 1)Acid-Base Theory 2)PBE pH Calculation 3)Distribution Coefficient 3.2.2 Titration Curves3.3.3 Acid-Base Indicators3.3.4 Applications Acid-Base TitrationThis is a quick accurate method for d
2、etermining acidic or basic substances in many samples.Several inorganic acids and basesHundreds of organic speciesThis titrant is typically a strong acid or base.The sample species can be either a strong or weak acid or base.3.2.1 Acid-Base Equilibria1.Acid-Base Theory Arrhenius Theory(Nobel Prize 1
3、903)Acid:any substance that ionizes in water to give hydrogen ions(H+).Hydrogen ions associates with the solvent to increase hydronium ion(H3O+)in solution.Base:ionizes in water to give hydroxyl ions(OH-)Brnsted Lowry TheoryAcid=Proton DonorBase=Proton Acceptor Acid BaseAcid Base HCl +H2O H3O+Cl-(St
4、rong)(Weak)H2CO3 +H2O H3O+HCO3-(Weak)(Strong)A Brnsted acid is a proton donor.A Brnsted base is a proton acceptor.Acid=H+BaseThese are conjugate pairs.A“strong”electrolyte is completely dissociated.A“weak”electrolyte is partially dissociated.Acid Dissociation ConstantBase Dissociation ConstantHA+H2O
5、 =H3O+A-A-+H2O =HA+OH-For any acid-base pair:Ka Kb=H+A-HAHA OH-A-=KwStrong acid-Ka Strong base-Kb Weak acid-Ka Weak base-Kb H3A=H+H2A-H2A-=H+HA2-HA2-=H+A3-For For PolyproticPolyprotic Acids:Acids:A3-+H2O=HA2-+OH-HA2-+H2O=H2A-+OH-H2A-+H2O=H3A+OH-For its Conjugate Bases:For its Conjugate Bases:Ka1 Kb3
6、=Ka2 Kb2=Ka3 Kb1=KwFor For PolyproticPolyprotic Acids:Acids:H3PO4 H2PO4-HPO42-PO43-Kb2Kb1Kb3Ka1Ka2Ka33.2.1 Acid-Base Equilibria2.Calculation of pH pH=-lgH+pH is the acidity expression of an aqueous solution:25 H+=1.010-7 mol/L pH=7.00 OH-=1.010-3 mol/L H+=1.010-11 mol/L pH=11.00(1)Proton balance equ
7、ation(PBE)a)H+obtained=H+lostb)Selecting zero levelsc)Judging the species that lose protons and d)obtain protonsd)Writing the PBE equationExample Write the PBE for the acid HA solutionIn the solution:the species that are present in sufficient amount are HA,H2O HA+H2O=H3O+A-H2O+H2O=H3O+OH-PBE:H3O+=A-
8、+OH-not containing HA,H2OAnother Example Write the PBE for the Na2CO3 solution In the solution:the species that are present in sufficient amount are CO32-,H2O CO32-+H2O=HCO3-+OH-HCO3-+H2O=H2CO3+OH-H2O+H2O=H3O+OH-PBE:HCO3-+H2CO3 +H+=OH-not containingCO32-,H2OWrite the PBE for Na2S solution?2.Calculat
9、ion of pH(2)Solutions of Strong Acids and BasesStrong Acid(HA):HA +H2O =H3O+A-H2O+H2O =H3O+OH-PBE:H3O+=A-+OH-Suppose A-=ca,at 25 C If c 10-6 mol/L,H3O+=A-=ca If c 10-6 mol/L,OH-=HB=cb If c 10-6 mol/L,Kw/OH-+cb=OH-Exact EquationExample What is the pH of a 0.004 mol/L solution of hydrochloric acid?cHC
10、l=0.004 mol/L H+=0.004 M pH =-log(0.004)=2.4(3)Solutions of Weak Acid/BaseFor Monoprotic Weak Acid HA PBE:H+=A-+OH-Ka=H+A-/HA OH-=Kw/H+If caKa 20 Kw,Kw is negligible,thus-Approximate EquationIf the concentration of the weak acid is not too low,that is ca/Ka 500-Simplified Equation-Simplified Equatio
11、nSimilarly,the simplified equation of a weak base concentration is-Simplified Equation-Simplified EquationExampleA solution contains 6.1gL-1 of benzonic acid,C6H5COOH(苯甲酸、安息香苯甲酸、安息香),the Ka for benzonic acid is 6.310-5=10-4.2.calculate the pH.Solution(4)Dissociation of Polyprotic Acid/BasePolyprotic
12、 acids ionize in steps:The solution contains H2A,HA-and A2-,calculating its pH is complicated.For a solution containing H2A or H2A+HA-The second dissociation will have little effect and can be ignored.The pH of the solution is calculated from the Ka1 expression.If ExampleCalculate the pH of a 0.15 m
13、olL-1 solution of malonic acid,CH2(COOH)2.The dissociation constants for malonic acid are Ka1=10-2.85 and Ka2=10-5.66.SolutionThe second dissociation is ignored and H2A=0.15 H+Amphiprotic Solution -can accept or donate a protonSuch as HCO3-,HPO42-,H2PO4-,NH4Ac,etc.PBE:H+H2A=A2-+OH-Dissociations in H
14、A-solution:PBE:H+H2A=A2-+OH-Example Calculate the pH of a solution of sodium hydrogen malonate,HOOC-CH2-COONa.The dissociation constants for malonic acid are pKa1=2.85 and pKa2=5.66.Solutions:unless the solution is very diluteExample Calculate the pH of a solution having,at equilibrium,a hydrogen ma
15、lonate ion HA-concentration of 0.15 mol/L and a malonate ion A2-concentration of 0.05 mol/L.Solutions:(5)Buffers A buffered solution resists changes in pH when acids or bases are added or when dilution occurs.Buffer=Acid+its Conjugate Basee.g.HAc-NaAc H2CO3-HCO3-H2PO4-HPO42-Henderson-Hasselbalch Equ
16、ation:The Derivative ProcessKa:the HA acid dissociationTake logsRearrangeFor any acidsExampleFind the pH of a solution prepared by dissolving 12.43 g of tris-(hydroxymethyl)aminomethane(FW 121.136)plus 4.67g tris-hydrochloride(FW 157.597)in 1.00L water.(pKa=8.075)Solution:the moles of B and BH+in th
17、e solution areUsing the Henderson-Hasselbalch equation:Attention!SolutionpH1025380.05mol/L K tetroxalate1.671.681.690.05mol/L KH2 citrate3.8203.7763.7750.05mol/L KH Phthalate3.9984.0084.0300.025mol/L KH2PO4+0.0025mol/L Na2HPO46.9236.8656.8400.01mol/L Na2B4O79.3329.1809.0810.025mol/L NaHCO3+0.0025mol
18、/L Na2CO310.17910.0129.903Saturated solution Ca(OH)213.0012.4512.04Table 3-1 Standard Buffers and their pH Values3.Calculation of Species Present As a strong base reacts with a diprotic acid,the pH increases and the proportion of H2A,HA-and A2-in solution change.Distribution Coefficient-the fraction
19、 of each species at equilibrium,expressed as The distribution of the acidic and basic forms as a function of pH -Distribution GraphThe Role of Distribution Graph:1.Understand the acid-base titration deeply 2.Judge whether the polyprotic acid(base)can be titrated step by step The titration is a proce
20、ss that the fraction of each species and the pH change continuously.For example,a monoprotic acid HAFor example,a monoprotic acid HAThen Distribution Graph of HADiscuss:HA+A-=1 When pH=pKa;HA=A-=0.5 When pH pKa;A-is predominateFor example,a Diprotic Acid H2ASimilarlya.pH pKa1,H2A predominateb.pKa1 p
21、H pKa2,A2-predominated.pH=2.75,HA-is biggest HA-=0.938;H2A=0.028;A2-=0.034(H2C2O4)Discussion of H2A Distribution GraphFor a Triprotic Acid H3ADistribution Graph of H3PO4For Acid HnA阿司匹林阿司匹林pH=1.0pH=8.4 假假设设 H+,A-等等离离子子不不能能穿穿透透隔隔膜膜,HA分分子子可可自自由由通通过过隔隔膜膜.达达平平衡衡时时,隔隔膜膜两两边边的的HA浓度相等,浓度相等,即即HA血血=HA胃胃 阿阿司司匹
22、匹林林是是一一种种弱弱酸酸(即即乙乙酰酰水水杨杨酸酸),pKa=3.5.计计算算阿司匹林在胃中的吸收比率。阿司匹林在胃中的吸收比率。pH=7.4 pH=1.0 血浆血浆 隔膜隔膜 胃胃药物的吸收方式可表示为药物的吸收方式可表示为H+A-HAHA H+A-HA=血血HA c血血=胃胃HAc胃胃=c血血c总药总药c血血c血血+c胃胃c血血c胃胃=1+血血HA胃胃HA=1+H胃胃(H血血+Ka)(H胃胃+Ka)H血血=1+=c血血c总药总药99.99%3.2.2 Titration Curves For each type of titration,our goal is to construct
23、a graph showing how the pH changes as the titrant is added.By doing this,we understand what is happening during the titration and are able to interpret an experimental titration curve.Titration curves We assume that you are always smart enough to use either a strong acid or base as your titrant.This
24、 will results in your types of titrations for simple acids or bases.Strong Acid vs.Strong Base Strong Acid vs.Weak Base Strong Base vs.Strong Acid Strong Base vs.Weak AcidIn the titration,there are three regions:(1)Before reaching the equivalence point(2)At the equivalence point(3)After the equivale
25、nce point Titration Curves A plot of ml titrant(or%titration)vs pH will result in a typical titration curve.Titration Curves Example:Construct a titration curve for the titration of 100ml of 0.10M HCl with 0.10M NaOH.0%Titration pH=-log0.10=1.00After 10ml NaOH100%Titration Equivalence point pH=7Note
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