CPU与汇编语言上机考试题.pdf

《CPU与汇编语言上机考试题.pdf》由会员分享，可在线阅读，更多相关《CPU与汇编语言上机考试题.pdf（69页珍藏版）》请在淘文阁 - 分享文档赚钱的网站上搜索。

1、请任意输入一个字符串，将该串倒序后在屏幕上显示。.model small.stack 10h.datastring db 100 dup(50)#db：defined b y te,定义 100 个字节，初始化为 50.codestart:mov ax,datamov ds,ax#ds：数据段寄存器，对应全局变量lea dx,string#lea：存储器地址偏移量存入dxmov ah,Oah#Oah：中断号，从键盘接收字符串并放入缓冲区（回车键结束）。缓冲区首地址存于dx。缓冲区第2字节开始实际存字符。int21h#转入中断子程序的入口mov dl,Oah#Oah：换行符的 asc 码mov

2、ah,02h#02h：显示输出int 21hxor bh,bhmov bl,string1 1#缓冲区的第。字节存入最多接收的字符数，第1字节存放实际输入的字数lop:mov dl,stringbx+1mov ah,02hint21hdec bxjnz lopmov ah,4ch#4ch：退出程序int 21h2.end start请任意输入一个字符串，.model small.stack 10h.databuf db 100 dup(50)count 1 db OOhcount2 db OOhstrl db*num of space is:$str2 db num of A is$.code

3、统计其中空格和A 的个数，并将结果显示在屏幕上。#定 义 100字 节 初 始 化 50#初始化0 space个数#A 个数start:mov ax,datamov ds,axlea dx,bufmov ah,Oahint21hmov dl,Oahmov ah,02hint 21h#换行#显示输出xor bh,bh#0mov bl,bufllop:mov al,buffbx+1#最后一个字符xor al,*#space?jz spacemov al,bufbx+1xor al,A1jz char_Anext:dec bxjnz lopjz showspace:add countl,Olhjmp

4、 nextchar_A:add count2,Olhjmp nextshow:lea dx,str Imov ah,09h#显示字符串int21hmov dl,count 1add dl,30hmov ah,02hint21hmov dl,Oah#换行mov ah,02h#输出int21hlea dx,str2mov ah,09hint21hmov dl,count2add dl,30hmov ah,02hint21hmov dl,Oahmov ah,02hint21hmov ah,4chint21hend start3.请任意输入一个字符串，将其中的空格全部删除，并将结果显示在屏幕上。.mo

5、del small.stack 10h.databufdb 100dup(50).codestart:mov ax,datamov ds,axlea dx,bufmov ah,Oahint 21hmov dl,Oahmov ah,02hint21hxor bh,bhmov bl,buflmov si,0002hlop:mov al,bufsixor al,11jz nextjnz shownext:dec bxjz breakinc sijmp lopshow:mov dl,bufsimov ah,02hint21hjmp nextbreak:mov ah,4chint21hend start

6、4.请任意输入一个字符串，将其中A 换成C C,并将结果显示在屏幕上。.model small.stack 10h.databufdb 100dup(50).codestart:mov ax,datamov ds,axlea dx,bufmov ah,Oahint21hmov dl,Oahmov ah,02hint21hxor bh,bhmov bl,bull 1 mov si,0002hlop:mov al,bufsixor al,Ajz show_ccjnz show_charnext:dec bxjz breakinc sijmp lopshow_cc:mov dl,Cmov ah,02

7、hint21hint21hjmp nextshow_char:mov dl,bufsimov ah,02hint21hjmp nextbreak:mov ah,4chint21hend start5.请任意输入一个字符串，将其中大写字母换成小写字母，并将结果显示在屏幕上。.model small.stack 10h.databuf db 100 dup(50).codestart:mov ax,datamov ds,axlea dx,bufmov ah,Oahint 21hmov dl,Oahmov ah,02hint21hxor bh,bhmov bl,bull 1 lea si,buf+2

8、;cld;将标志寄存器的方向标志位d f清零lop:lodsb;将子串中SI指针所指的一个字节装入ALcmp al,Wjnb ifupjb show_charnext:dec bxjnz lopjz breakifup:cmp al,Zjbe show_downja show_charshow_char:mov dl,almov ah,02hint21hjmp nextshow_down:add al,a Amov dl,almov ah,02hint21hjmp nextbreak:mov ah,4chint 21hend start6.请任意输入一个字符串，将其中的英文字母全部删除，并将结

9、果显示在屏幕上。.model small.stack 10h.databufdb 100dup(50).codestart:mov ax,datamov ds,axlea dx,bufmov ah,Oahint 21hmov dl,Oahmov ah,02hint 21hxor bh,bhmov bl,bufllea si,buf+2cldlop:lodsbcmp al,Wjnb ifupjb show_charnext:dec bxjnz lopjz breakifup:cmp al,Zjbe nextcmp al,ajnb ifdownifdown:cmp al,zjbe nextjmp

10、show_charshow_char:mov dl,almov ah,02hint21hjmp nextbreak:mov ah,4chint21hend start二、7.现有一组字符串为data,name,time,file,code,path,user,exit,quitjext,请编写程序从键盘输入4 个字符的字符串，若存在将其修改为disk,并将结果在显示器上显示。.model small;换明用的简略定义，这与希不用管.stack 10h;微楼破，一 皴 逑 与；STACK SEGM ENT；DB 20 DUP（?）STACK ENDS.datastring db Oah,data

11、,nam e,tim e,file,code,path,usenquit,texts/b u f db 100 dup（50）rpl db disk;数据做一皴格式；DATA SEGM ENT;string db Oah,data,nam e,tim e,file,code,path,user,quit,texts/;b u f db 10 dup（50）rpl db disk；DATA ENDS;代恁窗一般格式.code;CODE S E G M E N T；ASSUME CS：CODE.DS：DATA,SS：STACKS T A R T PRO C FA R；PUSH DX；MOV AX.

12、0；PUSH AX；MOV AX.DATAS；MOV DS.AX 恒旬之后的copy笆耒就能用；住患多的代喝S T A R T E N D P；GODES ENDS；EN D S T A R Tstart:mov ax.datamov ds,axmov es.axlea dx.bufmov ah.Oah；10孑DOS调用物入冬行串int 21hlea si.string 1;也 置 循环拓傕lea di.b u fcldlop:mov ex.0004hrepz empsb:吮破船人学符串与S I专前秀后的字符事jn z next:判断字符串袅看相等，彳 等&健 跳 出and ex.ex:赳断聂

13、看个字符都和第jz replacejm p nextnext:add si.exmov al.siemp Ql.;判断聂看到字符串借屋jz breakinc silea di.buf2jm p lopreplace:;为小sub si.0004hmov di.silea si.rplmov cxt 0004hrep movsbbreak:;输出lea dx.stringmov ah.09hin t 21 h.exitend s ta rtDATAS SEGM ENTstring db Oah.,d atanam e.tim e,file.code.path.user,quit.text$,b

14、u f db 10 dup（50）rpl db diskDATAS ENDSSTACKS S E G M E N Tdb 20 dup(?)STACKS ENDSCODES S E G M E N TASSUME CS：CODES,DS：DATAS.SS：STACKSS T A R T：MOV AX.DATASMOV DS.AXmov es.axlea dx,bufmov ah.Oahint 21hlea si.stringllea di.buf2c ld【清 方 而 杼 安 危，施 标 去(f la g s)高 存 器 的D F=0,地 位 就 豺si、di信 加；必 是s td则把D F=

15、1,他 征 养 豺 减J也 口 使D F的 保 为0,在 加 打 串 海 行 时，使 他 处 松 递 傀 的 方 式 或 化，这 祥 使 孑 调 整 和 关 段 的 的 当 筋 韭 豺。康 蓝 金 幺STD(S eT Direction f lo g)的 外 名 储 果 和 反，即笈D F的 保 为1。lop:mov ex.0004hrepz em psb 比 装 物 人 学 符$与S I当 京 柒 向 的 学 名 串 jn z nextand ex.exjz replaceJmp nextnext:add si.exmov al.siemp al.jz breakinc silea di.b

16、uf2jm p lopreplace:sub si.0004h【偌 2 花 豺 的 伟,我 而 下 一 个 敢 据 mov di.silea si.rplmov ex.0004hrep movsbbreak:lea dx.stringmov ah.09hint 21 hMOV AH.4OHINT 21HCODES ENDSEN D S T A R T8.现有一组字符串为ram,yes,red,the,get,for,and,key,not,may,请编写程序将他们按ASCII大小排序，并在显示器上显示。.model small.stack 10h.dataraw db Oah,Yam,yes,

17、red,the,get,for,and,key,not,may$count equ($-raw-1)/4.codestart:mov ax,datamov ds,axxor bh,bhmov bl,countcldlop:lea si,rawldec bxand bx,bxjz breaklopl:mov ex,0003hlop2:mov al,siemp al,si+4ja exchangejb noexchdec exjz nextinc sijmp lop2next:add si,exinc simov al,si+4xor al,$jz lopinc sijmp loplnoexch:

18、dec exjmp nextexchange:mov al,sijxchg al,si+4xchg al,sijdec exjz nextinc sijmp exchangebreak:lea dx,rawmov ah,09hint21h.exitend start现有一组字符串为data,name,time,file,code,path,user,exit,quit,text,请编写程序从键盘输入4 个字符的字符串，若存在将其删除，并在显示器上显示。data segmentbufl db data,name,time,file,code,path,user,quit,text$buf2 db

19、 50 dup(?)input db 10 dup(50)data endscode segmentassume ds:data,cs:codestart:mov ax,datamov ds,axmov es,axlea dx,inputmov ah,Oahint21hlea bx,buf2lea si,bufllea di,input2mov ex,0004hcldlop:empsbjnz copydec exjz deletejmp lopnext:mov al,si-1emp al,$jz breaklea di,input2mov ex,0004hjmp lopcopy:add si,

20、exsub si,0005hmov di,bxmov ex,0005hrep movsbmov bx,dijmp nextdelete:inc sijmp nextbreak:mov al,$mov bx-1,almov dl,Oahmov ah,02hint21hlea dx,buf2mov ah,09hint21hmov ah,4chint21hcode endsend start10.现有一组字符串为 data,name,time,file,code,path,user,exit,quit,text,请编写程序将上述字符串排序(升序)并插入disk使其人仍然有序，并在显示器上显示。dat

21、a segmentbufl db data,name,time,file,code,path,user,quit,text$count 1 equ($-bufl)/5buf2 db data,name,time,file,code,path,user,quit,text,disk$count2 equ($-bu/5data endsstack segment stackdb IOdup(?)stack endscode segmentassume ds:data,cs:codesort proc farpush silop:pop sipush sidec bxand bx,bxjz brea

22、klopl:mov ex,0004hlop2:mov al,siemp al,si+5ja exchangejb noexchdec exjz nextinc sijmp lop2next:mov al,si+5xor al,$jz lopinc sijmp loplexchange:mov al,sixchg al,si+5xchg al,siinc sidec exjz nextjmp exchangenoexch:add si,exjmp nextbreak:mov dl,Oahmov ah,02hint21hpop dxmov ah,09hint21hretsort endpstart

23、:mov ax,datamov ds,axmov bx,count 1 +1lea si,buflcall sortmov bx,count2+1lea si,buf2call sortmov ah,4chint21hcode endsend start三、11.键盘输入一个十进制数(字类型)，以十六进制的形式输出。data segmentbuf db 10 dup(50)hex db 4 dup(O),h;Oah,coefdw 0001htemp dw OOOOhdata endscode segmentassume cs:code,ds:datastart:mov ax,datamov d

24、s,axlea dx,bufmov ah,Oahint21hmov bl,buff 1 xor bh,bhxor ax,axmov al,Olhlop:mov al,bufbx+1xor ah,ahsub al,30hmov dx,coefmul dxadd temp,axmov ax,coefmov dx,10mul dxmov coef,axdec bxjz showjmp lopshow:mov bx,0mov cl,12lopl:mov ax,tempshr ax,cland al,OOOlhmov hexbx,alsub cl,4inc bxcmp bx,4jz lop2jmp lo

25、plmov bx,4lop2:mov al,hexbx-1cmp al,9ja charjmp numnext:dec bxjz breakjmp Iop2char:add hexfbx-1,a1-Oahjmp nextnum:add hexbx-1,Ojmp nextbreak:mov dl,Oahmov ah,02hint 21hlea dx,hexmov ah,O9hint21hmov ah,4chint21hcode endsend startax存 字 a l存字节cb w 字节一字(扩展)读取输入数值入bxxchg ax,bx 存入 axmov ex,10mul exadd bx,

26、ax循环移位：rol12.键盘输入一个十进制数(字类型)，以二进制的形式输出。data segmentbufdb 10dup(50)hex db 16 dup(O),rb Oah,$coefdw 0001htemp dw OOOOhdata endscode segmentassume cs:code,ds:datastart:mov ax,datamov ds,axlea dx,bufmov ah,Oahint 21 hmov bl,buflxor bh,bhxor ax,axmov al,Olhlop:mov al,bufbx+1xor ah,ahsub al,30hmov dx,coef

27、mul dxadd temp,axmov ax,coefmov dx,10mul dxmov coef,axdec bxjz showjmp lopshow:mov bx,0mov cl,15lopl:mov ax,tempshr ax,cland al,000 Ihmov hexbx,aladd hexbx,30hsub cl,1inc bxcmp bx,16jz breakjmp loplbreak:mov di,Oahmov ah,02hint21hlea dx,hexmov ah,09hint 2lhmov ah,4chint21hcode endsend start13.键盘输入一个

28、二进制数(字类型)，以十六进制的形式输出。data segmentbuf db 20 dup(50)temp dw OOOOhcoefdw 0001haim db 4 dup(O),h,Oah,$data endscode segmentassume cs:code,ds:datastart:mov ax,datamov ds,axlea dx,bufmov ah,Oahint21hmov dl,Oahmov ah,02hint21hmov al,buf 1 xor ah,ahmov si,axlop:mov al,si+1sub al,30hxor ah,ahmov dx,coefmul d

29、xadd temp,axmov ax,coefmov dx,0002hmul dxmov coef,axdec sijz showjmp lopshow:mov bx,0mov cl,12lopl:mov ax,tempshr ax,cland al,OOOfhmov aimbx,alsub cl,4inc bxcmp bx,4jz lop2jmp loplmov bx,4lop2:mov al,aimfbx-1cmp al,9ja charjmp numnext:dec bxjz breakjmp lop2char:add aimbx-1 ,a*-Oahjmp nextnum:add aim

30、bx-1,*0*jmp nextbreak:mov dl,Oahmov ah,02hint 21hlea dx,aimmov ah,09hint21hmov ah,4chint21hcode endsend start14.键盘输入一个二进制数（字类型），以十进制的形式输出。data segmentbufdb 20 dup(50)temp dw OOOOhcoefdw 0001haim db 5 dup(O),Oah,data endscode segmentassume cs:code,ds:datastart:mov ax,datamov ds,axlea dx,bufmov ah,Oah

31、int21hmov dl,Oahmov ah,02hint21hmov al,buflxor ah,ahmov si,axlop:mov al,si+1sub al,30hxor ah,ahmov dx,coefmul dxadd temp,axmov ax,coefmov dx,0002hmul dxmov coef,axdec sijz showjmp lopshow:mov si,5mov ax,tempmov bx,10move:xor dx,dxdiv bxmov aimsi-1,diadd aimsi-1,30hdec sijz breakjmp movebreak:mov dl,

32、Oahmov ah,02hint 21hlea dx,aimmov ah,09hint 2lhmov ah,4chint21hcode endsend start15.键盘输入一个十六进制数(字类型)，以十进制的形式输出。data segmentbuf db 10 dup(5O)temp dw OOOOhcoef dw 0001 haim db 5 dup(O),Oah,$data endscode segmentassume cs:code,ds:datastart:mov ax,datamov ds,axlea dx,bufmov ah,Oahint21hmov dl,Oahmov ah,

33、02hint 21 hmov al,buf 1 xor ah,ahmov si,axlop:mov al,si+1cmp al,a1jb numjmp charnext:xor ah,ahmov dx,coefmul dxadd temp,axmov ax,coefmov dx,001 Ohmul dxmov coef,axdec sijz showjmp lopnum:sub al,30hjmp nextchar:sub al,a-10jmp nextshow:mov si,5mov ax,tempmov bx,10move:xor dx,dxdiv bxmov aimsi-1,dladd

34、aimsi-1 J,30hdec sijz breakjmp movebreak:mov dl,Oahmov ah,02hint21hlea dx,aimmov ah,09hint21hmov ah,4chint 21hcode endsend start16.键盘输入一个十六进制数(字类型)，以二进制的形式输出。data segmentbuf db 50 dup(50)temp dw OOOOhcoefdw 0001hhex db 16 dup(O),rb,Oah,data endscode segmentassume cs:code,dsidatainput proc farlea dx,

35、bufmov ah,Oahint 21 hmov di,Oahmov ah,02hint21hretinput endpprint proc farmov bx,0mov cl,15lopl:mov ax,tempshr ax,cland al,OOOlhmov hexfbx,aladd hexbx,30hsub cl,1inc bxcmp bx,16jz breakjmp loplbreak:mov dl,Oahmov ah,02hint21hlea dx,hexmov ah,09hint 21hretprint endpstart:mov ax,datamov ds,axcall inpu

36、tmov al,buflxor ah,ahmov si,axlop:mov al,si+1cmp al,a1jb numjmp charnext:xor ah,ahmov dx,coefmul dxadd temp,axmov ax,coefmov dx,001 Ohmul dxmov coef,axdec sijz showjmp lopnum:sub al,30hjmp nextchar:sub al,a-10jmp nextshow:call printmov ah,4chint21hcode endsend start 输 入、转换及显示均用子程序形式书写。程序能够循环接收不同的十进制

37、数，并对之处理，当按下非数字键时退出主程序，返回操作系统。四、17.将一组有符号数中的负数求和，并统计负数的个数，并在屏幕上以十进制的形式显示结果。38H,4AH,0C5H,83H,9CH,0B4H,7FH,0C4H,05H,0F5Hdata segmentbufdb 38h,4ah,0c5h,83h,9ch,0b4h,7fh,0c4h,05h,Of5hcount equ$-bufsum dw 0cout dw 0temp dw 0aim db 5 dup(O),Oah,$data endscode segmentassume cs:code,ds:dataprint proc farmov

38、si,5mov ax,tempmov bx,10move:xor dx,dxdiv bxmov aimsi-1,dladd aimsi-1,30hdec sijz breakjmp movebreak:lea dx,aimmov ah,09hint21hretprint endpstart:mov ax,datamov ds,axmov si,countxor ex,exxor ah,ahlop:mov al,si-1emp al,0jl negativejmp nextnext:dec sijz showjmp lopnegative:add cout,1cbwsub sum,axjmp n

39、extshow:mov ax,coutmov temp,axmov dl,Oahmov ah,02hint 21hcall printmov dl,Oahmov ah,02hint21hmov ax,summov temp,axmov dl,mov ah,02hint21hcall printmov ah,4chint 21hcode endsend start18.键盘输入十个数，分别统计0 到 9,10到 99,100以上的数的个数，并显示结果。data segmentstrl db 09$str2db,10-99:$str3 db 100$buf db 10 dup(50)count d

40、b 3 dup(O)data endscode segmentassume cs:code,ds:datastart:mov ax,datamov ds,axmov ex,10lop:lea dx,bufmov ah,Oahint21hmov bl,buflxor bh,bhdec blmov al,Olhadd countfbx,aldec exjz showmov dl,Oahmov ah,02hint 21hjmp lopshow:mov si,3iften:mov al,countsi-1xor al,Oahjz changedec sijz breakjmp iftenchange:

41、mov countsi-1,a1-01break:lea dx,strlmov ah,09hint 21hmov dl,count0add dl,30hmov ah,02hint 21hmov dl,Oahint 21hlea dx,str2mov ah,09hint 21 hmov dl,countladd dl,30hmov ah,02hint 21hmov dl,Oahint21hlea dx,str3mov ah,09hint 21hmov dl,count2add dl,30hmov ah,02hint 21hmov dl,Oahint 21hmov ah,4chint 21hcod

42、e endsend start19.键盘输入两组数743216、527864,按 BCD码求和，并将结果显示在屏幕上。data segmentbufl db 20 dup(50)buf2 db 20 dup(50)buf3 db 20 dup(50)data endscode segmentassume cs:code,ds:datainput proc farmov ah,Oahint21hmov bx,dxmov al,bx+1xor ah,ahmov si,axlop:mov al,30hsub bx+si+1,aldec sijz breakjmp lopbreak:mov dl,Oa

43、h;空格，换行mov ah,02h;输出换行int 2lhretinput endpstart:mov ax,datamov ds,axlea dx,buflcall inputlea dx,buf2call inputmov bl,bufllxor bh,bhxor ah,ahmov buf3bx+1,*$add_lop:mov al,buflbx+1add al,buf2bx+1add al,ahxor ah,ahaaamov buf3bx,aladd buf3bx,30hdec bxjz ifcpjmp add_lopifcp:and ah,ahjz nocpjmp cpnocp:lea

44、 dx,buf3ljmp showcp:mov al,0add al,ahmov buf3bx,aladd buf3bx,30hlea dx,buf3show:mov ah,09hint21hmov ah,4chint 21hcode endsend start2 0.键盘输入下列两组十进制数，求其和，并将结果显示在屏幕上357894184653142521.键盘输入一串二进制数lah,7ch,Obah,3ah,45h,63h求其和，并将结果显示在屏幕上。22.从键盘输入一串可显示字符(以回车符结束)，并按字母、数字、空格分类计数，然后显示出这三类统计的结果。data segmentbufdb

45、 100dup(50)strl db The num of num is$str2 db The num of char is:$str3 db The num of space is:$cl dwOc2 dw 0c3 dwOtemp dw 0aim db 4 dup(O),Oah,$data endscode segmentassume cs:code,ds:dataprint proc farmov si,5mov ax,tempmov bx,10move:xor dx,dxdiv bxmov aimsi-1,diadd aimsi-1,30hdec sijz break 1jmp mov

46、ebreak 1:lea dx,aimmov ah,09hint21hmov dl,Oahmov ah,02hint21hretprint endpifnum proc farcmp al,01jb break2cmp al,9ja break2add cl,1break2:retifnum endpifchar proc farcmp al,A,jb break3cmp al,Zjbe pluscmp al,ajb break3cmp al,z*jbe plusplus:add c2,1break3:retifchar endpifspace proc farcmp al,1jnz brea

47、k4add c3,1break4:retifspace endpstart:mov ax,datamov ds,axlea dx,bufmov ah,Oahint21hmov dl,Oahmov ah,02hint21hmov bl,buflxor bh,bhlop:mov al,buffbx+1call ifnumcall ifcharcall ifspacedec bxjz breakjmp lopbreak:lea dx,strlmov ah,09hint21hmov ax,clmov temp,axcall printlea dx,str2mov ah,09hint21hmov ax,

48、c2mov temp,axcall printlea dx,str3mov ah,09hint21hmov ax,c3mov temp,axcall printmov ah,4chint 21hcode endsend start五、2 3.编写程序，将十个字的有符号数中最大、最小值求出，并在显示器上输出。125ah,4357h,Of5Oh,0b43h,4ac4h,7454h,8bl5h,0a2a4h,Of3ch,00f6hdata segmentbufdw 125ah,4357h,Of5Oh,0b43h,4ac4h,7454h,8bl5h,0a2a4h,Of3ch,00f6htemp dw

49、0aim db 4 dup(O),h,Oah,$maxnum dw 0minnum dw 0strl db max num is:$*str2 db min num is:$*data endscode segmentassume cs:code,ds:dataprint proc farmov bx,0mov cl,12lopl:mov ax,tempshr ax,cland al,OOOfhmov aimfbx,alsub cl,4inc bxcmp bx,4jz lop2jmp loplmov bx,4lop2:mov al,aimbx-1 jcmp al,9ja charjmp num

50、next:dec bxjz breakjmp lop2char:add aimbx-1,a*-Oahjmp nextnum:add aimfbx-11,*0*jmp nextbreak:lea dx,aimmov ah,09hint21hretprint endpstart:mov ax,datamov ds,axmov bx,18mov ax,bxmov ex,bxlop:sub bx,2emp ax,bxjl maxemp ex,bxjg minnextt:emp bx,0jz exitjmp lopmax:mov ax,bxjmp nexttmin:mov ex,bxjmp nextte