施工现场临时用电量计算问题详解.docx

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1、施工现场临时用电量计算问题详解 全套序号用电设备 名称技术数据数量换算后的容量(kw)总容量(kw)1塔吊QT40(TQ2-6) llOkw2台1102202电焊机JC = 50%24 KVACO4)=0.874台24.3697.443消防水泵1台15153地泵11101104插入式震 动器H250 5.5KW8台1.5125木工机具砂轮机1.5KW1台1.5木工 园锯MJ2254.5KW2台4.59木工 平板 刨ME5037.5KW2台7.5156空气压缩 机6KW2台61237套丝机4KW2台488钢筋加工钢筋弯曲机GWJ405.6 KW2台489钢筋切断 机GJ40 42台4810调直机

2、7.5KW2台6.51311无齿锯(4)400)2台1.53533kw1现场用电大用电量施工项目主要有：桩基施工、混凝土结构施工、设备安装调试 等。2负荷计算：根据各种施工机械用量表，计算如下：S施工用电总容量SC施工动力用电设备所需总容量Pc用电设备总的有功计算负荷Pa用电设备总的有功率Kd同类设备的需要系数QC用电设备总的无功计算负荷2.1.塔吊组：PC1 = 110(kw) kdl = 0.7 tanp 二1.02 COScp = 0.7 n = 0.86PCI = 0.7x2x110/0.86PCl = 179kwQC1 = 178x1.0222插入式震动器组：PC2 = 1,5(kw

3、) kdl = 0.7 tanp C = 1.02 COScp = 0.7 n = 0.86PC2 = 9.78kw2.3. 砂轮机组：PC3 = 0.81kw2.4. 木工园锯组：PC4 = 4.5(kw) kdl = 0.7 tanp(t = 1.02 COScp = 0.7 n = 0.86PC4 = 7.3kw25木工平板刨组：PC5 = 7.5(kw) kdl = 0.7 tanp = 1.02 COScp = 0.7 n = 0.86PC5 = 12.21kw2.6. 空气压缩机组：PC6 = 6(kw) kdl = 0.7 tanp C = 1.02 COScp = 0.7 n

4、= 0.86PC6 = 0.7x2x6/0.86PC6 = 9.77kw2.7. 钢筋弯曲机组：PC7 = 4(kw) kdl = 0.7 tanp C = 1.02 COS(p = 0.7 n = 0.86PC7 = 0.7x2x4/0.86PC7 = 6.51kw2.8. 筋切断机组：PC8 = 6.52kw2.9. 调直机组：PC9 = 6.5(kw) kdl = 0.7 tanp (t = 1.02 COScp = 0.7 n = 0.86PC9 = 10.58kw2.10. 无齿锯组：PC10 = 1.5(kw) kdl = 0.7 tanp = 1.02 COScp = 0.7 n

5、 = 0.86PC10 = 2.44kw2.11. 焊机组：PC11 = 24.36(kw) kdl = 0.7 tanp C = 1.02 COScp = 0.7 n = 0.86PCll = 79.31kw2.12. 套丝机组：PC12 = 4(kw) kdl = 0.7 tanpd =1.02 COScp = 0.7 n = 0.86PC12 = 0.7x2x4/0.86PC12 = 6.51 kwQC12 = 2.13. 防水泵：PC13 = 15(kw) kdl = 0.7 tanp = 1.02 COScp = 0.7n = 0.86PC13 = 24.42 kw2.14. 地 泵

6、:PC14 = 110(kw) kdl = 0.7 tanp (t = 1.02 COS(p = 0.7n = 0.86PC14 = 0.7x1x110/0.86PCM = 89.53 kw3求总计算负荷取同时系数K = 0.7则PC 二 KWfPC=O.7(PC1 + PC2 +PC3+ PC4+ PC5 + PC6+PC7 +PC8+ PC9 + PC10=444.69kwS C 二 KQ c二 0.7(Q C1+ QC2 + QC3+Q C4+ Q C5+ QC6+QC7 + Q C8+ Q C9+ Q CIO + Q C11+ Q C12+ Q C13+ Q C14 )二 318KV.A4工地照明按动力负荷的10%考虑，则S=l.lxSC (KV.A)= 349.8(KV.A)变压器的容量经计算施工需要用电量为选一台500KV.A变压器方能够满足施工需要。